Find value of x- -49-x1-12

nbsp; √(49)=(x)^1/12 Raising both sides to the power of 24 = gt;49=(x)^24/12 = gt;x^2=49 = gt;x=7 ...

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Byju's Answer

Standard XII

Mathematics

Modulus of a Complex Number

Find value of...

Question

Find value of $x$ :
$\sqrt[24]{49} = {(x)}^{1 / 12}$

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Solution

$\sqrt[24]{49} = {(x)}^{1 / 12}$
Raising both sides to the power of $24$
$=> 49 = {(x)}^{24 / 12}$
$=> x^{2} = 49$
$=> x = 7$

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Find value of x:24√49=(x)1/12

24√49=(x)1/12Raising both sides to the power of 24=>49=(x)24/12=>x2=49=>x=7

Find value of $x$ :
$\sqrt[24]{49} = {(x)}^{1 / 12}$

$\sqrt[24]{49} = {(x)}^{1 / 12}$
Raising both sides to the power of $24$
$=> 49 = {(x)}^{24 / 12}$
$=> x^{2} = 49$
$=> x = 7$