Find value of x- -4x-7-5-0

The correct option is D 33 nbsp; √(4x 7) 5=0 = gt;√(4x 7)=5 Cubing both sides, we get = gt;(4x 7)=125 = gt;4x=125+7 = g ...

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Standard VIII

Mathematics

Cube-Root of a Negative Perfect Cube

Find value of...

Question

Find value of $x$ :
$\sqrt[3]{4 x - 7} - 5 = 0$

125

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25

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49

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33

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Solution

The correct option is D $33$
$\sqrt[3]{4 x - 7} - 5 = 0$
$=> \sqrt[3]{4 x - 7} = 5$
Cubing both sides, we get
$=> (4 x - 7) = 125$
$=> 4 x = 125 + 7$
$=> 4 x = 132$
$=> x = 33$

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Question 105

If $5^{3 x - 1} \div 25 = 125$ , then find the value of x .

Find the values of the following:
(i) |11 $-$ 25|

(ii) |9| + | $-$ 9|

(iii) |6×3 + ( $-$ 6)×3|

(iv) |x+5 $-$ (7+x)|

(v) |4| × | $-$ 8|

(vi) | 3(3 $-$ 8) + ( $-$ 5)|

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Find value of x:3√4x−7−5=0

The correct option is D 33 3√4x−7−5=0=>3√4x−7=5Cubing both sides, we get=>(4x−7)=125=>4x=125+7=>4x=132=>x=33

Find value of $x$ :
$\sqrt[3]{4 x - 7} - 5 = 0$

The correct option is D $33$
$\sqrt[3]{4 x - 7} - 5 = 0$
$=> \sqrt[3]{4 x - 7} = 5$
Cubing both sides, we get
$=> (4 x - 7) = 125$
$=> 4 x = 125 + 7$
$=> 4 x = 132$
$=> x = 33$