Question

Find $x$ and $y$ intercepts of the given line:

$4x-y-7=0$

• A. $\frac{x}{\frac{4}{7}}-\frac{y}{7}=1,a=\frac{4}{7},b=-7$
• B. $\frac{x}{\frac{4}{7}}+\frac{y}{-7}=1,a=\frac{4}{7},b=-7$
• C. $\frac{x}{\frac{7}{4}}-\frac{y}{7}=1,a=\frac{7}{4},b=7$
• D. $\frac{x}{\frac{7}{4}}+\frac{y}{-7}=1,a=\frac{7}{4},b=-7$

Answer 1

The correct option is D $\frac{x}{\frac{7}{4}}+\frac{y}{-7}=1,a=\frac{7}{4},b=-7$

Given equation is $4x-y-7=0$ ........ $\left(i\right)$

Any line can be represented in two-intercept form i.e. in the form of $\frac{x}{a}+\frac{y}{b}=1$, where $a$ is $x-$intercept and $b$ is $y-$intercept.

Let's represent $\left(i\right)$ in two-intercept form

$4x-y-7=0$

$⟹4x-y=7$

$⟹\frac{4x}{7}-\frac{y}{7}=1$

$⟹\frac{x}{\frac{7}{4}}+\frac{y}{-7}=1$

$a=\frac{7}{4},b=-7$

Hence, option D is correct.