Question

First bunch of bananas has $\left(1/4\right)$ again as many bananas as a second bunch. If the second bunch has $3$ bananas less than the first bunch, then the number of bananas in the first bunch is

• A. $9$
• B. $10$
• C. $12$
• D. $15$

Answer 1

Answer: (D)

$15$

Let the number of bananas in the second bunch be $x$.
Then, number of bananas in the first bunch $=x+\frac{1}{4}x=\frac{5}{4}x$.
So, $\frac{5}{4}x-x=3\iff 5x-4x=12\iff x=12$.
$\therefore$ Number of bananas in the first bunch $=(\frac{5}{4}\times 12)=15$.