Five grams of $K C l O_{3}$ yields 3.0 g of $K C l$ and 1.4 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of $\pm 0.4 %$ error?

True

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False

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Solution

The correct option is A
True

According to gram - molecular volume law, 22.4 L of all gases and vapours at STP weigh equal to their molecular weights denoted in grams.

$∴$ Weight of 1.36 L of oxygen at STP =32 $\times$ $\frac{1.4}{22.4} = 2 g$

Weight of KCl formed = 3 g (given)

$∴$ Total weight of product (KCl + $O_{2}$ )

= 3 + 2 = 5 g

Error = 5 - 5 = 0 g

$∴ % e r r o r = 0$ $\times$ $\frac{100}{5}$ = 0

Hence, the law of conservation of mass is valid within limits of $- 0.4 %$ error. Thus, the law is supported.

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Similar questions

Five grams of $K C l O_{3}$ yield 3.041 g of $K C l$ and 1.36 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of $\pm 0.4 %$ error?

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(K C l O_{3})

. Decomposition, of potassium chlorate gives potassium chloride

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. How many moles and how many grams of

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Q. A sample of

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Calculate (i) Weight of oxygen product (ii) Weight of

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and

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KClO3 on heating decomposes to give KCl and Oxygen. What is the volume of oxygen liberated at NTP by 0.1mol of KClO3?

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Five grams of KClO3 yields 3.0 g of KCl and 1.4 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of ±0.4% error?

Five grams of $K C l O_{3}$ yields 3.0 g of $K C l$ and 1.4 L of oxygen at standard temperature and pressure. Do these figures support the law of conservation of mass within limits of $\pm 0.4 %$ error?