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Question

Five isolated capacitors are connected as shown in the figure. Find the potential at the junction O


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Solution

Let V0 be the potential at point OThe potential at point O can be given byV0=C1V1+C2V2+C3V3+C4V4+C5V5C1+C2+C3+C4+C5From the data given in the question,

C1=2μF , C2=5μF , C3=10μF , C4=5μF and C5=3μF

V1=10V , V2=15V , V3=2V , V4=4V and V5=5V

Substituting the given data we get,

V0=2×10+5×15+10×2+5×4+3×52+5+10+5+3

V0=15025

V0=6 volts

Accepted answers: 6 ,6.0 , 6.00


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