Five isolated capacitors are connected as shown in the figure. Find the potential at the junction ′O′
Let V0 be the potential at point ′O′The potential at point ′O′ can be given byV0=C1V1+C2V2+C3V3+C4V4+C5V5C1+C2+C3+C4+C5From the data given in the question,
C1=2μF , C2=5μF , C3=10μF , C4=5μF and C5=3μF
V1=10V , V2=15V , V3=2V , V4=4V and V5=5V
Substituting the given data we get,
V0=2×10+5×15+10×2+5×4+3×52+5+10+5+3
⇒V0=15025
⇒V0=6 volts
Accepted answers: 6 ,6.0 , 6.00