Question

Five students A, B, C, D and E are competing in a long-distance race. Each student’s probability of winning the race is given below:

$A\to 20\%,B\to 22\%,C\to 7\%,D\to 15\%,E\to 36\%$

(iii) Find the sum of probabilities given

Answer 1

Given:

$P\left(A\right)=20\%$

$P\left(B\right)=22\%$

$P\left(C\right)=7\%$

$P\left(D\right)=15\%$

$P\left(E\right)=36\%$

Sum of all probabilities $=P\left(A\right)+P\left(B\right)+P\left(C\right)+P\left(D\right)+P\left(E\right)$

$=20\%+22\%+7\%+15\%+36\%$

$=100\%$

= 1

Hence, the sum of the probabilities is $100\%$or 1.