Five workers take $12$ days to weed a field. How many days would $6$ workers take? How many would $15$ take

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Solution

$1$ st part

We have,

Worker $W_{1} = 5$

Weed a field in days $= D_{1} = 12 d a y s$

If,
Take worker $W_{2} = 6$

Then, Days $D_{2} = ?$

Then, we know that,

$W_{1} D_{1} = W_{2} D_{2}$

$5 \times 12 = 6 \times D_{2}$

$D_{2} = \frac{5 \times 12}{6}$

$D_{2} = 10 d a y s$

$2$ nd Part,

If worker $W_{3} = 15$

Then,

Days $D_{2} = ?$

Then, we know that,

$W_{1} D_{1} = W_{3} D_{3}$

$5 \times 12 = 15 \times D_{3}$

$D_{3} = \frac{5 \times 12}{15}$

$D_{3} = 4 d a y s$

Hence, this is the answer.

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Five workers take 12 days to weed a field. How many days would 6 workers take? How many would 15 take

1st part We have, Worker W1=5 Weed a field in days=D1=12days If,Take worker W2=6 Then, Days D2=? Then, we know that, W1D1=W2D2 5×12=6×D2 D2=5×126 D2=10days 2nd Part, If workerW3=15 Then, Days D2=? Then, we know that, W1D1=W3D3 5×12=15×D3 D3=5×1215 D3=4days Hence, this is the answer.

Five workers take $12$ days to weed a field. How many days would $6$ workers take? How many would $15$ take