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Question

Five years ago a man was seven times as old as his son. Five years hence, the father will be three times as old as his son. Find their present ages.

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Solution

5 years ago,

Let age of son = x years

Then, age of father = 7x years

Present age of son = x + 5 years

and age of father = 7x + 5 years

5 years hence,

age of son = x + 5 + 5 = x + 10

and age of father = 7x + 5 + 5 = 7x + 10

According to the condition :

7x+10=3(x+10)

7x+10=3x+30

7x3x=3010=20

4x=20

x=204=5

Present age of son =x+5=5+5=10 years and

Age of father =7x+5=7×5+5=35+5=40 years


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