Five years hence, the age of jacob will be three times that of his son. Five years ago, Jacob's age was seven times that of his son. What are their present ages?
[2 Marks]

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Solution

Let Jacobs age be x and his son’s age be y

x+ 5 = 3 y + 15 (1)

x-5 = 7 y – 35 (2) [1 Mark]

On Equation (2)–(1),

4 y = 40

y = 10

x = 40 [1 Mark]

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Q. Question 3 (vi)
Form the pair of linear equations for the following problems and find their solution by substitution method:
Five years hence, the age of Jacob will be three times that of his son. Five years ago, Jacob's age was seven times that of his son. What are their present ages?

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Five years hence, the age of jacob will be three times that of his son. Five years ago, Jacob's age was seven times that of his son. What are their present ages? [2 Marks]

Let Jacobs age be x and his son’s age be y x+ 5 = 3 y + 15 (1) x-5 = 7 y – 35 (2) [1 Mark] On Equation (2)–(1), 4 y = 40 y = 10 x = 40 [1 Mark]

Five years hence, the age of jacob will be three times that of his son. Five years ago, Jacob's age was seven times that of his son. What are their present ages?
[2 Marks]

Let Jacobs age be x and his son’s age be y

x+ 5 = 3 y + 15 (1)

x-5 = 7 y – 35 (2) [1 Mark]

On Equation (2)–(1),

4 y = 40

y = 10

x = 40 [1 Mark]