Floor tiles are $25 c m$ squares. How many tiles will be needed for a rectangle lawn $12 m$ long and $10 m$ wide. Find the total cost at the rate of $R s 8 p e r$ tile.

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Solution

Given Area of tils = $25 c m^{2}$

Given Dmersion of lawn = $12 \times 10 m$

Area of low = $12 \times 10 m$ $= 120 m^{2}$

Total titels needed = $\frac{120 \times 10}{25} = 48000.$

cost of tile = 8Rs/tile

Total cost = $8 \times 48000$ $= R s 384000$

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Floor tiles are 25 cm squares. How many tiles will be needed for a rectangle lawn 12 m long and 10 m wide. Find the total cost at the rate of Rs 8per tile.

Given Area of tils = 25cm2Given Dmersion of lawn = 12×10mArea of low = 12×10m =120m2Total titels needed = 120×1025=48000.cost of tile = 8Rs/tileTotal cost = 8×48000=Rs 384000

Floor tiles are $25 c m$ squares. How many tiles will be needed for a rectangle lawn $12 m$ long and $10 m$ wide. Find the total cost at the rate of $R s 8 p e r$ tile.

Given Area of tils = $25 c m^{2}$

Given Dmersion of lawn = $12 \times 10 m$

Area of low = $12 \times 10 m$ $= 120 m^{2}$

Total titels needed = $\frac{120 \times 10}{25} = 48000.$

cost of tile = 8Rs/tile

Total cost = $8 \times 48000$ $= R s 384000$