Flux ϕ (in webers) in a closed circuit of resistance 10 ohm varies with time t (in seconds) according to the equation ϕ=6t2−5t+1. What is the magnitude of the induced current in 0.25 second :
A
0.8 A
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B
1.2 A
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C
0.6 A
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D
0.2 A
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Solution
The correct option is C 0.2 A ϕ=6t2−5t+1e=dϕdt=12t−5att=0.25sec|e|=(12/4−5)=|3−5|=2i=e/R=2/10=0.2A