Following are the transition metal ions of $3 d$ series:
$T i^{4 +}, V^{2 +}, M n^{3 +}, C r^{3 +}$
(Atomic numbers: $T i = 22, V = 23, M n = 25, C r = 24)$
Answer the following:
(i) Which ion is most stable in an aqueous solution and why?
(ii) Which ion is a strong oxidising agent and why?
(iii) Which ion is colourless and why?

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Solution

(i) $T i^{4 +}$ is most stable as it has completely filled 3p orbital.
(ii) $M N^{3 +}$ is the strongest oxidising agent as it requires only one electron to half fill its 3d orbital
(iii) $T i^{4 +}$ will be colorless due to its empty 3d orbital.

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T i^{4 +}, V^{2 +}, M n^{3 +}, C r^{3 +}

(i) 2 M n O_{4}^{-} + 16 H^{+} + 5 S^{2 -} \to (i i) K M n O_{4} H e a t - -- \to

T i^{4 +}, V^{2 +}, M n^{3 +}, C r^{3 +}

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Which one of the following ions is the most stable in aqueous solution?
(Atomic number. Ti = 22, V = 23, Cr = 24, Mn = 25)

T i = 22, V = 23, C r = 24, M n = 25

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S c^{3 +}, V^{3 +}, T i^{4 +}, M n^{2 +}

S c = 21, V = 23, T i = 22, M n = 25

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