CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
3
You visited us 3 times! Enjoying our articles? Unlock Full Access!
Question

Following chemical species were reported for water sample from a well

Species Concentration
(milliequivalent/L)
Chloride (Cl−) 15
Sulphate (SO2−4) 15
Carbonate (CO2−3) 05
Bicarbonate (HCO−3) 30
Calcium (Ca2+) 12
Magnesium (Mg2+) 18
pH 8.5


Alkalinity present in the water in mg/L as CaCO3


A
5000
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
1750
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
1500
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
250
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 1750
Total hardness is due to multivalent cations(Ca2+,Mg2+)

Total hardess
= milliequivalent of Ca2+ + milliequivalent of Mg2+
=12+18

=30 milliequivalent/L
=30 milliequivalent CaCO3
=30× equivalent weight of CaCO3 mg/L
=30×50mg/L
=1500mg/LasCaCO3

Alkalinity is due to
(CO3,HCO3OH) [major source]

Alkalinity = Milliequivalent of CO2+3 + Milliquivalent of HCO3

=05+30

=35 milliequivalent/L

=(35×eq.wt.ofCaCO3/L)mg/L

=35×50mg/L

=1750mg/LasCaCO3

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Oxidation Number and State
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon