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Question

Following chemical species were reported for water sample from a well

Species Concentration
(milliequivalent/L)
Chloride (Cl) 15
Sulphate (SO24) 15
Carbonate (CO23) 05
Bicarbonate (HCO3) 30
Calcium (Ca2+) 12
Magnesium (Mg2+) 18
pH 8.5


Alkalinity present in the water in mg/L as CaCO3


A
5000
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B
1750
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C
1500
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D
250
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Solution

The correct option is B 1750
Total hardness is due to multivalent cations(Ca2+,Mg2+)

Total hardess
= milliequivalent of Ca2+ + milliequivalent of Mg2+
=12+18

=30 milliequivalent/L
=30 milliequivalent CaCO3
=30× equivalent weight of CaCO3 mg/L
=30×50mg/L
=1500mg/LasCaCO3

Alkalinity is due to
(CO3,HCO3OH) [major source]

Alkalinity = Milliequivalent of CO2+3 + Milliquivalent of HCO3

=05+30

=35 milliequivalent/L

=(35×eq.wt.ofCaCO3/L)mg/L

=35×50mg/L

=1750mg/LasCaCO3

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