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Byju's Answer
Standard XII
Mathematics
Higher Order Derivatives
Following fun...
Question
Following function is continous at the point
x
=
2
f
(
x
)
=
{
1
+
x
,
w
h
e
n
x
<
2
5
−
x
,
w
h
e
n
x
≥
2
A
True
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B
False
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Solution
The correct option is
A
True
Given
f
(
x
)
=
{
1
+
x
,
x
<
2
5
−
x
x
≥
2
lim
x
→
2
−
f
(
x
)
=
1
+
(
2
)
=
3
lim
x
→
2
+
f
(
x
)
=
5
−
(
2
)
=
3
f
(
2
)
=
5
−
2
=
3
⟹
lim
x
→
2
−
f
(
x
)
=
f
(
x
)
=
lim
x
→
2
+
f
(
x
)
Hence the function is continous at
x
=
2
Suggest Corrections
0
Similar questions
Q.
Let
f
(
x
)
=
{
x
2
+
k
,
w
h
e
n
x
≥
0
−
x
2
−
k
,
w
h
e
n
x
<
0
. If the function
f
(
x
)
be continous at
x
=
0
, then
k
=
Q.
Find the value of
k
for which
f
(
x
)
=
k
x
+
5
,
w
h
e
n
x
≤
2
and
f
(
x
)
=
x
−
1
,
w
h
e
n
x
>
2
is continuous at
x
=
2
.
Q.
Find the value of k for which
f
(
x
)
=
k
x
+
5
,
w
h
e
n
x
≤
2
and
x
−
1
,
w
h
e
n
x
>
2
is continuous at
x
=
2
.
Q.
If
f
(
x
)
=
⎧
⎨
⎩
x
+
2
,
w
h
e
n
x
<
1
4
x
−
1
,
w
h
e
n
1
≤
x
≤
3
x
2
+
5
,
w
h
e
n
x
>
3
, then correct statement is-
Q.
Prove that
f
(
x
)
=
⎧
⎨
⎩
x
2
−
x
−
6
x
−
3
,
w
h
e
n
x
≠
3
5
,
w
h
e
n
x
=
3
is continuous at
x
=
3
.
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