Following is an enzymatic reaction that takes place in the human body:
$C O_{2} (a q) + H_{2} O (l) ⇌ H C O_{3}^{-} (a q) + H^{+} (a q)$
Select the correct statement(s) about this reaction.

Forward reaction occurs when the blood takes up

C O_{2}

in the tissues, and the reverse reaction occurs when the blood releases

C O_{2}

in the lungs

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Enzyme (carbonic anhydrase) increases the rate by a factor

10^{6}

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Both (a) and (b) are the correct statements

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None of the above options are correct

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Solution

The correct option is C Both (a) and (b) are the correct statements
a) $C O_{2}$ is taken in the forward reaction and released in the reverse reaction. Hence, the statement is correct.

b) Enzyme is carbonic anhydrase and it increases the rate of both forward and backward reactions by $10^{6}$ . Hence, it is also a correct statement.

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Similar questions

C O_{2} (a q) + H_{2} O (l) ⇌ H C O_{3}^{-} (a q) + H^{+} (a q)

C O_{3}^{2 -} + H_{2} O (l) = H C O_{3}^{-} + O H^{-} (a q)

C u (s) + N O_{3}^{-} (a q) + H^{+} (a q) \to C u^{2 +} (a q) + N O_{2} (g) + H_{2} O (l)

2 N O_{2} (g) + 2 O H^{-} (a q) \to N O_{3}^{-} (a q) + H_{2} O (l) + N O_{2}^{-}

N a N H_{2 (s)} + H_{2} O_{(l)} ⇌ N a_{(a q)}^{+} + O H_{(a q)}^{-} + N H_{3 (a q)}

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