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Applications of Electrolysis and Electrolytic Cell

Following rea...

Question

Following reaction is:
$M n O_{4}^{-} (a q) ⟶ M n O_{4}^{2 -} (a q)$

reduction

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oxidation

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neither oxidation nor reduction

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none of these

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Solution

The correct option is B reduction
The unbalanced half reaction $M n O_{4}^{-} (a q) ⟶ M n O_{4}^{2 -} (a q)$ is reduction.
The oxidation number of Mn in $M n O_{4}^{-}$ and $M n O_{4}^{2 -}$ is +7 and +6 respectively.
Thus, there is decrease in the oxidation number which indicates reduction.

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Similar questions

E_{R P}^{o}

M n O_{4}^{-} (a q) + 8 H^{+} + 5 e \to M n^{2 +} (a q) + 4 H_{2} O (l); E^{o} = + 1.52 V

M n O_{4}^{2 -} (a q) + 4 H^{+} + 2 e \to M n O_{2} (s) + 2 H_{2} O (l); E^{o} = + 2.26 V

2 M n O_{4}^{-} (a q) + 2 e \to 2 M n O_{4}^{2 -} (a q); E^{o} = + 0.56 V

M n^{3 +} + e \to M n^{2 +}; E^{o} = + 1.51 V

M n^{4 +} + e \to M n^{3 +}; E^{o} = 0.95 V

M n (O H)_{2} (s) + M n O_{4}^{-} (a q) \to M n O_{2} (s)

Balance the following redox reactions by ion-electron method:

(a) (aq) + I^– (aq) → MnO₂ (s) + I₂(s) (in basic medium)

(b) (aq) + SO₂ (g) → Mn²⁺ (aq) + (aq) (in acidic solution)

(d) + SO₂(g) → Cr³⁺ (aq) + (aq) (in acidic solution)

The oxidation half reaction for following reaction is

Fe²⁺(aq) + Cr₂O₇^2-(aq) → Fe³⁺ (aq) + Cr³⁺(aq)

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