For 2Ag- - C6H12 O6 - H2 O - 2 Ags - C6 H12 O7 - 2H- ln K of the change is-

The correct option is B 58.38 2Ag^+ + C_6H_12 O_6 + H_2 O #160; → 2 Ag(s) + C_6 H_12 O_7 + 2H^+ for #160;the reaction, #160;E^o = E^o_OP_glu ...

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Byju's Answer

Standard XII

Mathematics

Latus Rectum of Hyperbola

For 2Ag+ + ...

Question

For $2 A g^{+} + C_{6} H_{12} O_{6} + H_{2} O \to 2 A g (s) + C_{6} H_{12} O_{7} + 2 H^{+}$ , ln K of the change is:

66.13

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58.38

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28.30

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46.29

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Solution

The correct option is B $58.38$
$2 A g^{+} + C_{6} H_{12} O_{6} + H_{2} O \to 2 A g (s) + C_{6} H_{12} O_{7} + 2 H^{+}$
for the reaction, $E^{o} = E_{O P_{g l u c o s e}}^{o} + E_{R P_{A g^{+} / A g}}^{o} = - 0.05 + 0.80$
$E^{o} = 0.75 V$
According to Nernst equation:
$E = E^{o} - 0.0591 l o g Q / n$
At eqm, $E = 0$
So $E^{o} = \frac{0.0591}{2} l o g K$
$= 0.75 = \frac{0.0591}{2} l o g K$
$∴ l n K = 58.38$

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Similar questions

Q. The equilibrium constant for the redox change

[2 A g (N H_{3})_{2}^{+} + C_{6} H_{12} O_{6} + H_{2} O \to C_{6} H_{12} O_{7} + 2 A g (s) + C_{6} H_{12} O_{2} + 2 H^{+}]

is:

2 A g^{+} + C_{6} H_{12} O_{6} + H_{2} O \to 2 A g (s) + C_{6} H_{12} O_{7} + 2 H^{+}

Find

ln K

this reaction.

Tollen’s reagent is used for the detection of aldehyde, when a solution of $A g N O_{3}$ is added to glucose with $N H_{4} O H$ then gluconic acid is formed.

$A g^{+} + e^{-} \to A g;$ $E_{r e d}^{\circ} = 0.8 V$

$C_{6} H_{12} O_{6} + H_{2} O \to C_{6} H_{12} O_{7}$ (Gluconic acid) $+ 2 H^{+} + 2 e; E_{o x d}^{\circ} = - 0.05 V$

$A g (N H_{3})_{2}^{+} + e^{-} \to A g (S) + 2 N H_{3}; E^{\circ} = - 0.337 V$