For A(1,−2,4),B(5,−1,7),C(3,6,−2),D(4,5,−1), the projection of −−→AB on −−→CD is
A
(2√3,−2√3,2√3)
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B
313(4,1,3)
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C
(1,−1,1)
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D
(2,−2,2)
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Solution
The correct option is D(2,−2,2) −−→AB=4^i+^j+3^k −−→CD=^i−^j+^k Hence, the projection of −−→AB on −−→CD is ⎛⎜⎝−−→AB.−−→CD|−−→CD|⎞⎟⎠.^CD =(4−1+3√1+1+1).(^i−^j+^k√1+1+1) =2^i−2^j+2^k