For a 2-port network consisting of an ideal lossless transformer, the parameter $S_{21}$ (rounded off to two decimal places) for a reference impendance of $10 Ω$ , is

0.8

Open in App

Solution

The correct option is A 0.8
For ideal transformer of n : 1,
the scattering matrix is

$[\begin{matrix} S_{11} & S_{12} S_{21} & S_{22} \end{matrix}] = ⎡ ⎢ ⎢ ⎢ ⎢ ⎣ \begin{matrix} \frac{n^{2} - 1}{n^{2} + 1} & \frac{2 n}{n^{2} + 1} \frac{2 n}{n^{2} + 1} & (\frac{1 - n^{2}}{1 + n^{2}}) \end{matrix} ⎤ ⎥ ⎥ ⎥ ⎥ ⎦$

$S_{21} = \frac{2 n}{n^{2} + 1} = \frac{2 (2)}{2^{2} + 1} = \frac{4}{5} = 0.8$

Suggest Corrections

Similar questions

The ABCD matrix for a two-port network is defined by
$[\begin{matrix} V_{1} I_{1} \end{matrix}] = [\begin{matrix} A & B C & D \end{matrix}] [\begin{matrix} V_{2} - I_{2} \end{matrix}]$

The parameter B for the given two-port network(in ohms, correct to two decimal places) is