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Sign of Trigonometric Ratios in Different Quadrants

For a acute A...

Question

For a acute $△ A B C$ , the value of $\frac{cos (A + B)}{cos C}$ is

A

0

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B

- 1

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C

1

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D

cot (A + B)

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Solution

The correct option is B $- 1$
$A + B + C = π \Rightarrow A + B = π - C$

Now,
$\frac{cos (A + B)}{cos C} = \frac{cos (π - C)}{cos C} = - 1$

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Sign of Trigonometric Ratios in Different Quadrants

Standard XII Mathematics

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