For a biased die the probabilities for the different faces to turn up are given below - - Face 1 2 3 4 5 6- Probabilities 0-10 0-32 0-21 0-15 0-05 0-17 -The die is tossed you are told that either face one or face two has turned up- Then the probability that it is face one is -

The correct option is D 5/21 A→ P(1, 2)=0.1+0.32=0.42 P(1A)=P(A∩ 1)P(A) =0.10.42=521 A is the event that either face 1 or 2 occurs. ...

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Standard XI

Mathematics

Axiomatic Approach

For a biased ...

Question

For a biased die the probabilities for the different faces to turn up are given below :
$\begin{matrix} F a c e 1 & 2 & 3 & 4 & 5 & 6 P r o b a b i l i t i e s 0.10 & 0.32 & 0.21 & 0.15 & 0.05 & 0.17 \end{matrix}$
The die is tossed & you are told that either face one or face two has turned up. Then the probability that it is face one is :

1/6

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5/21

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Solution

The correct option is D 5/21
$A \to P (1, 2) = 0.1 + 0.32 = 0.42$

$P (\frac{1}{A}) = \frac{P (A \cap 1)}{P (A)}$

$= \frac{0.1}{0.42} = \frac{5}{21}$

A is the event that either face $1$ or $2$ occurs.

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For a biased die the probabilities for the different faces to turn up are given below :Face123456Probabilities0.100.320.210.150.050.17The die is tossed & you are told that either face one or face two has turned up. Then the probability that it is face one is :

The correct option is D 5/21A→P(1,2)=0.1+0.32=0.42P(1A)=P(A∩1)P(A)=0.10.42=521A is the event that either face 1 or 2 occurs.

The correct option is D 5/21
$A \to P (1, 2) = 0.1 + 0.32 = 0.42$

$P (\frac{1}{A}) = \frac{P (A \cap 1)}{P (A)}$

$= \frac{0.1}{0.42} = \frac{5}{21}$

A is the event that either face $1$ or $2$ occurs.