You visited us 3 times! Enjoying our articles? Unlock Full Access!

Gibb's Energy and Nernst Equation

For a cell Mg...

Question

For a cell $M g (s) | M g^{2 +} (a q) | | A g^{+} (a q) | A g$ , find the maximum work (in kJ) that can be obtained by operating the cell.
$E^{o} (M g^{2 +} / M g) = - 2.37 V, E^{o} (A g^{+} / A g) = 0.8 V$

Open in App

Solution

$M g (s) + 2 A g^{+} \to M g^{2 +} + 2 A g$
Given, $E_{M g^{2 +} / M g}^{o} = - 2.37 V$
$E_{(A g^{+} / A g)}^{o} = 0.8 V$
$E_{c e l l}^{o} = E_{c a t h o d e}^{o} - E_{a n o d e}^{o}$
$E_{c e l l}^{o} = 2.37 + 0.8 = 3.17 V$
Again, $maximum work obtained = n f E_{cell}^{o} = 2 \times 96500 \times 3.17 = 611810 J = 611.81 k J$

Suggest Corrections

Similar questions

M g (s) | M g^{2 +} (a q) | | A g^{+} (a q) | A g (s)

25^{o}

E_{M g / M g^{2 +}}^{o} = + 2.37 V

E_{A g^{+} / A g}^{o} = 0.80 V

M g | M g^{2 +} (a q .) ∥ A g^{+} (a q .) | A g

25^{\circ} C

E_{M g^{2 +} / M g}^{\circ} = - 2.37 v o l t

E_{A g^{+} / A g}^{\circ} = + 0.80 v o l t

M g^{2 +} + 2 e^{-} \to M g (s); E^{0} = - 2.37 V

A g^{+} (a q) + e^{-} \to A g (s); E^{0} = + 0.80 V

M g | M g^{2 +} | | A g^{2 +} | A g

25^{\circ} C

E_{M g / M g^{2 +}}^{\circ} = 2.37 v o l t

E_{A g^{2 +} / A g}^{\circ} = 0.80 v o l t

M g^{2 +}

10^{- 6} M

25^{o} C

M g (s) | M g^{2 +} (a q, 0.2 M) | | A g^{+} (a q, 1 \times 10^{- 3}) | A g (s)

E_{A g^{+} / A g}^{0} = + 0.8 V

E_{M g^{2 +} / M g}^{0} = - 2.37 V

Join BYJU'S Learning Program