For the cell reaction- Mg- Mg2-aq- Ag-aq-Agcalculate the equilibrium constant at 25-C and maximum work that can be obtained by operating the cell- E-Mg2-Mg - -2-37 volt and E-Ag-Ag - - 0-80 volt-

E^∘_cell = 0.80 + 2.37 = 3.17 volt log K_c = nE^∘_cell0.0591 = 2× 3.170.0591 = 107.2758 K_c = 1.89× 10^107 = nFE^∘ = 2× 96500× 3.17 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Equilibrium Constant from Nernst Equation

For the cell ...

Question

For the cell reaction,
$M g | M g^{2 +} (a q .) ∥ A g^{+} (a q .) | A g$
calculate the equilibrium constant at $25^{\circ} C$ and maximum work that can be obtained by operating the cell.
$E_{M g^{2 +} / M g}^{\circ} = - 2.37 v o l t$ and $E_{A g^{+} / A g}^{\circ} = + 0.80 v o l t$ .

Open in App

Solution

Suggest Corrections

Similar questions

M g | M g^{2 +} | | A g^{2 +} | A g

25^{\circ} C

E_{M g / M g^{2 +}}^{\circ} = 2.37 v o l t

E_{A g^{2 +} / A g}^{\circ} = 0.80 v o l t

M g (s) | M g^{2 +} (a q) | | A g^{+} (a q) | A g (s)

25^{o}

E_{M g / M g^{2 +}}^{o} = + 2.37 V

E_{A g^{+} / A g}^{o} = 0.80 V

M g (s) | M g^{2 +} (a q) | | A g^{+} (a q) | A g

E^{o} (M g^{2 +} / M g) = - 2.37 V, E^{o} (A g^{+} / A g) = 0.8 V

M g^{2 +} + 2 e^{-} \to M g (s); E^{0} = - 2.37 V

A g^{+} (a q) + e^{-} \to A g (s); E^{0} = + 0.80 V

M g_{(s)} + 2 A g_{(a q)}^{+} \to M g_{(a q)}^{2 +} + 2 A g_{(s)}

E_{M g^{2 +} / M g}^{0} = - 2.37 V

E_{A g^{+} / A g}^{0} = 0.80 V

[M g^{2 +}] = 0.001 M; [A g^{+}] = 0.0001 M

Join BYJU'S Learning Program