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Question

For a cell Mg(s) | Mg2+(aq) || Ag+(aq) | Ag. Calculate the equilibrium constant at 25°C. Also find the maximum work that can be obtained by operating the cell.
E0Mg2+/Mg=-2.37 V, E0 (Ag+/Ag) = 0.8 V

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Solution

The given cell isMg/Mg2+// Ag+/AgThe cell potential is E0 =E ox0 +E Red0 = E Mg/Mg2+0 +E Ag+/Ag0 = -(-2.37) + 0.8 = =3.17 VMaximum work done = G0 = - nFE0 = - 2 × 96500 × 3.17 = -611810 JE0= 0.0591n log KlogK= nE00.0591 = 2 ×3.170.0591K= A.log (107.27) = 1.86 × 10107

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