Question

For a certain reaction of order ‘n’, the half-life $\left(t_{\frac{1}{2}}\right)$ is given by, $t_{\frac{1}{2}}=\frac{2-\sqrt{2}}{k}\times C_0^{\frac{1}{2}}$, where k is a constant and $C_0$ is the initial concentration. Find 'n'.

Answer 1

Half life for $n^{th}\propto [reactant{]}^{1-n}$
So on comparing with $t_{\frac{1}{2}}=\frac{2-\sqrt{2}}{k}\times C_0^{\frac{1}{2}}$

$\frac{1}{2}=1-n$
$n=0.5$