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Reaction Quotient

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Question

For a chemical reaction $2 A_{(g)} ⇋ 3_{(g)}^{B}$ initial moles of a is 10 moles.At equilibrium point dod is(x=0.1). Find total moles present in container at equilibrium.

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Solution

$2 A ⇌ 3 B$
at $t = 0$ $10$ $0$
at equilibrium $10 (1 - 2 α)$ $10 (3 α)$
Total moles at equilibrium= $10 [1 - 2 α + 3 α]$
$= 10 (1 + α)$
$= 10 \times 1.1$
$= 11$

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