For a chemical reaction, ∆G will always be negative if:
A
∆H and ∆S both are +ve
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B
∆H and ∆S both are – ve
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C
∆H is negative and ∆S is positive
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D
∆H is positive and ∆S is negative
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Solution
The correct option is C ∆H is negative and ∆S is positive From gibbs helmholtz relations: ΔG=ΔH−TΔS
Now for ΔG to be always negative ΔH needs to be negative and ΔS needs to be positive.