Question

For a circular curve of radius 200 m, the coefficient of lateral friction of 0.15 and the design speed is 40 kmph. The equilibrium superelevation (for equal pressure on inner and outer wheel) would be

Answer 1

Equilibrium superelevation,

$e=\frac{V^2}{127R}=\frac{{40}^2}{127\times 200}$

$=0.0629\simeq 6.3\%$