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Nature of Oxides

For a conjuga...

Question

For a conjugate acid-base pair the relation between $K_{a}$ , $K_{b}$ :

K_{a} \times K_{b} = 1

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K_{a} / K_{b} = K_{w}

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K_{a} \times K_{b} = K_{w}

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K_{a} \times K_{b} = 14

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Solution

The correct option is C $K_{a} \times K_{b} = K_{w}$
For conjugate acid-base pairs, relation between $K_{a}$ and $K_{b}$ is given by

$K_{a} \times K_{b} = K_{w}$
where,
$K_{w}$ is auto-ionisation constant.
So, correct answer is option C.

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