For a dilute solution containing a nonvolatile solute, the molar mass of solute evaluated from
the osmotic pressure measurement is given as:

M_{2} = \frac{m_{2}}{V} \frac{R T}{π}

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M_{2} = \frac{m_{2}}{V} \frac{π}{R T}

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M_{2} = m_{2} \frac{R T}{π}

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M_{2} = m_{2} \frac{π}{R T}

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Solution

The correct option is C $M_{2} = \frac{m_{2}}{V} \frac{R T}{π}$
For a dilute solution containing a nonvolatile solute, the molar mass of solute evaluated from the osmotic pressure measurement is given as:
$M_{2} = \frac{m_{2}}{V} \frac{R T}{Π}$
$M_{2}$ = molar mass of solute.
$m_{2}$ = wt of solute.
$π$ = osmotic pressure.
So answer is A.

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For a dilute solution containing a nonvolatile solute, the molar mass of solute evaluated from the osmotic pressure measurement is given as:

The correct option is C M2=m2VRTπFor a dilute solution containing a nonvolatile solute, the molar mass of solute evaluated from the osmotic pressure measurement is given as:M2=m2VRTΠM2= molar mass of solute.m2= wt of solute.π= osmotic pressure.So answer is A.

For a dilute solution containing a nonvolatile solute, the molar mass of solute evaluated from
the osmotic pressure measurement is given as: