For a function given by y=f(t) and x=g(t). Thendydx can be expressed as df(t)dtdg(t)dt
True
False
Here x and y are represented parametrically in terms of t.
Now, dydx=dydtdxdt=df(t)dtdg(t)dt
The second derivative of a single valued function parametrically represented by x=ϕ(t) and y=ψ(t), ( where ϕ(t) and ψ(t) are different functions and ϕ′(t)≠0) is given by