Question

For a given chemical reaction $A\to B$ at $300K$ the free energy change is $-49.4kJmo{l}^{-1}$ and the enthalpy of reaction is $51.4kJmo{l}^{-1}$. The entropy change of the reaction is _____$J{K}^{-1}mo{l}^{-1}$.

Answer 1

$\Delta G=-49.4kJ/mol$

$\Delta H=51.4kJ/mol$

$\Delta G=\Delta H-T\Delta S$

$-49400=51400-300\Delta S$

$\Delta S=\frac{+100800}{300}=336J{K}^{-1}mo{l}^{-1}$