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Derivation of Kp and Kc

For a given e...

Question

For a given exothermic reaction $K_{P}$ and $K_{P}^{'}$ are the equilibrium constants at temperatures $T_{1}$ and $T_{2}$ respectively. Assuming that heat of reaction is constant in temperature range between $T_{1}$ and $T_{2}$ is readily observed that__________.

A

K_{p} > K_{p}^{'}

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B

K_{p} = \frac{1}{K_{p}^{'}}

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C

K_{p} = K_{p}^{'}

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D

K_{p} < K_{p}^{'}

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Solution

The correct option is A $K_{p} > K_{p}^{'}$
Given
Kp is equilibrium constant at T1
Kp' is equilibrium constant at T2.
Solution
The equilibrium constant at two different temperatures is given by
$l o g \frac{K_{p}^{^{'}}}{K_{p}} = \frac{Δ H^{0}}{2.303 R} (\frac{1}{T_{1}} - \frac{1}{T_{2}})$
For exothermic reaction T1 < T2
Therefore Kp > Kp'
The correct option is A

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