For a Ist order decomposition of A as given

Therefore rate constant (K) for the overall decomposition of A is

K = k_{1} + k_{2} . . . . . . . . . . . + k_{n}

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K = (k_{1} + k_{2} . . . . . . . . . . . + k_{n}) /_{n}

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K = k_{1} \times k_{2} \times . . . . . . . . . . . \times k_{n}

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K = k_{1} k_{2} + k_{2} k_{3} + . . . . . . . . . . . + k_{n - 1} k_{n}

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Solution

The correct option is A $K = k_{1} + k_{2} . . . . . . . . . . . + k_{n}$
$\frac{- d [A]}{d t} = k_{1} [A] + k_{2} [A] + . . . . . . . . . . . . . . . + k_{n} [A] = (k_{1} + k_{2} + . . . . . . . . . . + k_{n}) [A] = K_{o v e r a l l} [A]$

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For a Ist order decomposition of A as given Therefore rate constant (K) for the overall decomposition of A is

The correct option is A K=k1+k2...........+kn−d[A]dt=k1[A]+k2[A]+...............+kn[A]=(k1+k2+..........+kn)[A]=Koverall[A]

For a Ist order decomposition of A as given

Therefore rate constant (K) for the overall decomposition of A is

The correct option is A $K = k_{1} + k_{2} . . . . . . . . . . . + k_{n}$
$\frac{- d [A]}{d t} = k_{1} [A] + k_{2} [A] + . . . . . . . . . . . . . . . + k_{n} [A] = (k_{1} + k_{2} + . . . . . . . . . . + k_{n}) [A] = K_{o v e r a l l} [A]$