For a matrix A=⎛⎜⎝100210321⎞⎟⎠, if U1,U2 and U3 are 3×1 column matrices satisfying AU1=⎛⎜⎝100⎞⎟⎠,AU2=⎛⎜⎝230⎞⎟⎠,AU3=⎛⎜⎝231⎞⎟⎠ and U is 3×3 matrix whose columns are U1,U2 and U3. Then sum of the elements of U−1 is
A
6
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B
0 (zero)
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C
1
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D
23
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Solution
The correct option is B0 (zero) Let Ui=⎛⎜⎝aibici⎞⎟⎠,i=1,2,3 AU1=⎛⎜⎝a12a1+b13a1+2b1+c1⎞⎟⎠=⎛⎜⎝100⎞⎟⎠
⇒a1=1,b1=−2,c1=1
Similarly, AU2=⎛⎜⎝a22a2+b23a2+2b2+c2⎞⎟⎠=⎛⎜⎝230⎞⎟⎠
⇒a2=2,b2=−1,c2=−4
Similarly, AU3=⎛⎜⎝a32a3+b33a3+2b3+c3⎞⎟⎠=⎛⎜⎝231⎞⎟⎠
⇒a3=2,b3=−1,c3=−3
Therefore, the matrix U is U=⎛⎜⎝122−2−1−11−4−3⎞⎟⎠
U−1=13⎛⎜⎝−1−20−7−5−3963⎞⎟⎠ The sum of the element of U−1 is zero.