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Ohm's Law in Scalar Form

For a metalli...

Question

For a metallic conductor, current versus voltage graph is drawn at two different temperatures $T_{1}$ and $T_{2}$ From the graph it follows.

T_{1} = T_{2}

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T_{1} > T_{2}

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T_{1} < T_{2}

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nothing can be decided

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Solution

The correct option is B $T_{1} > T_{2}$
Here slope $\frac{V}{I} = R$
$R \propto T$
So $T_{1} > T 2$
(because slope at $T_{1}$ is more than $T_{2}$

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For a metallic conductor, current versus voltage graph is drawn at two different temperatures T1 and T2 From the graph it follows.

The correct option is B T1>T2Here slope VI=RR∝TSo T1>T2(because slope atT1 is more than T2

For a metallic conductor, current versus voltage graph is drawn at two different temperatures $T_{1}$ and $T_{2}$ From the graph it follows.

The correct option is B $T_{1} > T_{2}$
Here slope $\frac{V}{I} = R$
$R \propto T$
So $T_{1} > T 2$
(because slope at $T_{1}$ is more than $T_{2}$