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Question

For a positive integer n, find the value of (1-i)n1-1in.

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Solution

(1-i)n1-1in=1-in1-i4in [ i4=1] =1-in1-i3n =1-in1+in [ i3=-i] =(1-i)(1+i)n =(1-i2)n =2n [ i2=-1]

Thus, the value of (1-i)n1-1in is 2n.

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