Question

For a projectile, the ratio of maximum height reached to the square of flight time is $(g=10m{s}^{-2})$

• A. 5 : 4
• B. 5 : 2
• C. 5 : 1
• D. 10 : 1

Answer 1

The correct option is A

5 : 4

$H=\frac{u^{2}si{n}^2\theta }{2g}$ and $T=\frac{2usin\theta }{g}$
So $\frac{H}{T^2}=\frac{\frac{u^{2}si{n}^2\theta }{2g}}{\frac{4u^{2}si{n}^2\theta }{g^2}}=\frac{g}{8}=\frac{5}{4}$