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Standard XII

Chemistry

Activation Energy

For a reactio...

Question

For a reaction $A_{2} + B_{2} ⇌ 2 A B$ the figure shows the path of the reaction in absence and presence of a catalyst. What will be the energy of activation for forward $(E_{f})$ and backward $(E_{b})$ reaction in presence of a catalyst and $△ H$ for the reaction? the dotted curve is the path of reaction in presence of a catalyst.

E_{f} = 60 k J / m o l, E_{b} = 70 k J / m o l, △ H = 20 k J / m o l

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E_{f} = 20 k J / m o l, E_{b} = 20 k J / m o l, △ H = 50 k J / m o l

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E_{f} = 70 k J / m o l, E_{b} = 20 k J / m o l, △ H = 10 k J / m o l

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E_{f} = 10 k J / m o l, E_{b} = 20 k J / m o l, △ H = - 10 k J / m o l

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Solution

The correct option is D $E_{f} = 10 k J / m o l, E_{b} = 20 k J / m o l, △ H = - 10 k J / m o l$
$E_{f} = 70 - 60 = 10 k J / m o l$

$E_{b} = 70 - 50 = 20 k J / m o l$

$△ H = 50 - 60 = - 10 k J / m o l$
Option D is correct

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Similar questions

Q. The activation energy for the forward reaction

X \to Y

60 K J

{m o l}^{- 1}

and

Δ H

- 20 K J

{m o l}^{- 1}

. The activation energy for the backward reaction

Y \to X

is:

Q. For a given reaction, energy of activation for forward reaction

(E_{a f})

80 k J / m o l

Δ H = - 40 k J / m o l

for the reaction. A catalyst lowers

E_{a f}

20 k J / m o l

. The ratio of energy of activation for reverse reaction before and after addition of catalyst is:

Q. The energies of activation for forward and reverse reactions for

(A_{2} + B_{2} ⇌ 2 A B)

are

180 k J

mol

^{- 1}

and

200 k J

mol

^{- 1}

respectively. The presence of a catalyst lowers the activation energy of both (forward and reverse) reactions by

100 k J

mol

^{- 1}

. The enthalpy change of the reaction

(A_{2} + B_{2} \to 2 A B)

in the presence of catalyst will be (in kJ mol

^{- 1}

)

The energies of activation for forward and reverse reactions for $A_{2} + B_{2} ⇌ 2 A B$ are $180 k J m o l^{- 1}$ and $200 k J m o l^{- 1}$ respectively. The presence of a catalyst lowers activation energy of both reactions by $100 k J m o l^{- 1}$ . The enthalpy change of the reaction $(A_{2} + B_{2} \to 2 A B)$ in the presence of a catalyst will be (in kJ $m o l^{- 1}$ )

Q. The activation energy for the forward reaction

X

\to

Y

60 k J

m o l^{- 1}

and

Δ H

- 20 k J

m o l^{- 1}

. The activation energy for the reverse reaction is:

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The correct option is D Ef=10 kJ/mol,Eb=20 kJ/mol,△H=−10 kJ/molEf=70−60=10 kJ/molEb=70−50=20 kJ/mol△H=50−60=−10 kJ/molOption D is correct

The correct option is D $E_{f} = 10 k J / m o l, E_{b} = 20 k J / m o l, △ H = - 10 k J / m o l$
$E_{f} = 70 - 60 = 10 k J / m o l$

$E_{b} = 70 - 50 = 20 k J / m o l$

$△ H = 50 - 60 = - 10 k J / m o l$
Option D is correct