Question

For a reaction, $A+2B⟶C,$ the amount of $C$ formed by starting the reaction with 5 moles of $A$ and $8$ moles of $B$ is:

• A. 5 mol
• B. 8 mol
• C. 16 mol
• D. 4 mol

Answer 1

The correct option is D 4 mol

As from rection $A+2B\to C$

It is clear that 1 mole of $A$ reacts with 2 moles of $B$ to form 1 mole of $C.$

$\therefore$ 4 moles of $A$ will react with $2\times 4=8$ moles of $B$ to form 4 moles of $C$

Here, $B$ is limiting reagent. 1 mole of $A$ remains unreacted.

Thus, the correct option is $D$