The correct option is C 0.24
In this reaction, 4A + 2B + 3C → A4B2C3
We have been provided with moles of A, B & C. We need to find the limiting reagent here, which is the one whose ratio of actual moles and stoichiometric coefficients is the smallest.
A:14 = 0.25
B:0.62 = 0.3
C:0.723 = 0.24
This makes C the limiting reagent which decides the amount of products formed.
It is clear that 3 mol of C produces 1 mol of A4B2C3.
By the unitary method, 0.72 mol of C produces 0.24 mol of it.