Question

In the reaction 4A+2B+3C = A₄ B_{2​​​​​​​} C₃ ​​​​​​​what will be the number of moles of product formed, starting from 1 mole of A , 0.6 mole of B and 0.72 mole of C?

Answer 1

4A+2B+3C = A4 B2 C3

The mole ratio of A:A4B2C3 is 4:1,
B:A4B2C3 is 2:1, and C:A4B2C3 is 3:1

so moles of product formed is

1mole A*1moleA4B2C3/4mole A = 0.25mol A4B2C3 formed

0.6mol B*1molA4B2C3/2mol B=0.3 mol A4B2c3 formed

0.72mol B*1molA4B2C3/3mol C =0.24mol A4B2C3 formed.

so A produces 0.25mol product,
B produces 0.3mol product
C produces 0.24mol product

Here thelimiting reactant is C and the answer should be considered to be formed from C.
the least quantity formed is from C that is 0.24 mol .
Once the limiting reactant gets used up the reaction comes to completion that is the reason we take 0.24 mol as the answer.