For a reaction A+B→C, the rate law is written as r=k[A2][B]. Doubling the concentration of A without changing concentration of B increases the rate of reaction by:
A
2 times
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B
4 times
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C
8 times
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D
16 times
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Solution
The correct option is D4 times A+B→C, the rate law is written as r=k[A2][B]. Rate of reaction is proportional to [A]2. Doubling the concentration of A without changing concentration of B increases the rate of reaction r1=k[2A]2[B]=4r the rate will be increased by 4 times.