For a reaction AB(g)⇔A(g)+B(g), AB is 33% dissociated at a total pressure of P, then:
A
P=KP
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B
P=3KP
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C
P=4KP
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D
P=8KP
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Solution
The correct option is CP=8KP AB⇌A+B No. of mole initially, AB−1,A−0,B−0 No. of moles at equilibrium, AB−(1−13),A−13,B−13 Total no. of moles=23+13+13=43 KP=PA×PBPAB KP=(13/43)P×(13/43)P((23)/(43))P KP=18P ∴P=8KP