For a reversible reaction- AK2K1-B- Ist order in both the directions- the rate of reaction is given by-

The correct option is D K_1[A] K_2[B] AK_2K_1⇌B Rate=K_1[A] K_2[B] for a reversible reaction of Ist order opposed by Ist order. ...

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Standard XII

Physics

Calorimetry

For a reversi...

Question

For a reversible reaction, $A_{1} K_{2} B$ , Ist order in both the directions, the rate of reaction is given by:

K_{1} [A]

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- K_{2} [B]

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K_{1} [A] + K_{2} [B]

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K_{1} [A] - K_{2} [B]

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Solution

The correct option is D $K_{1} [A] - K_{2} [B]$
$A_{1} K_{2} B$
$R a t e = K_{1} [A] - K_{2} [B]$ for a reversible reaction of Ist order opposed by Ist order.

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For a reversible reaction, AK1⇌K2B, Ist order in both the directions, the rate of reaction is given by:

The correct option is D K1[A]−K2[B]AK1⇌K2BRate=K1[A]−K2[B] for a reversible reaction of Ist order opposed by Ist order.

For a reversible reaction, $A_{1} K_{2} B$ , Ist order in both the directions, the rate of reaction is given by:

The correct option is D $K_{1} [A] - K_{2} [B]$
$A_{1} K_{2} B$
$R a t e = K_{1} [A] - K_{2} [B]$ for a reversible reaction of Ist order opposed by Ist order.