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Question

For a reversible reaction : N2+O22NO
Activation energy of the backward reaction is lower than that of forward reaction. The slope of k verse 1/T graph will be:

A
zero
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B
H2.303R
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C
H2.303R
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D
ΔHR
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Solution

The correct option is C H2.303R
For reactions whose forward direction has less activation energy, the graph has -ve slope, indicating, a faster reaction in the forward direction.
It is given in the question that the backward reaction has a lower EA than the forward reaction. this means graph has a positive slope.
Slope of graph=ΔH2.303R
Hence answer is [C].

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