For a reversible reaction : N2+O2⇌2NO Activation energy of the backward reaction is lower than that of forward reaction. The slope of k verse 1/T graph will be:
A
zero
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B
−H2.303R
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C
H2.303R
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D
−ΔHR
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Solution
The correct option is CH2.303R For reactions whose forward direction has less activation energy, the graph has -ve slope, indicating, a faster reaction in the forward direction.
It is given in the question that the backward reaction has a lower EA than the forward reaction. this means graph has a positive slope.