For a satellite very close to surface of earth, we get time period of satellite equal to

85 minutes

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Solution

The correct option is A 85 minutes
$T = 2 π \sqrt{\frac{R_{E}}{g}} = 2 π \sqrt{\frac{64 \times 10^{5}}{9.8}} s ≅ 85 m i n u t e s$

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For a satellite very close to surface of earth, we get time period of satellite equal to

The correct option is A 85 minutesT=2π√REg=2π√64×1059.8s≅85 minutes

The correct option is A 85 minutes
$T = 2 π \sqrt{\frac{R_{E}}{g}} = 2 π \sqrt{\frac{64 \times 10^{5}}{9.8}} s ≅ 85 m i n u t e s$