For a transistor, the value of $α$ is 0.8. The transistor is connected in common-emitter configuration. The change in the collector current when the base current changes by 6 mA is:

6 mA

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4.8 mA

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24 mA

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8 mA

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Solution

The correct option is C 24 mA
$α = 0.8$
$β = \frac{α}{1 - α} = \frac{0.8}{0.2} = 4$
$\frac{Δ I_{c}}{Δ I_{B}} = 4 \Rightarrow Δ I_{c} = 4 \times 6 = 24 m A$

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For a transistor, the value of α is 0.8. The transistor is connected in common-emitter configuration. The change in the collector current when the base current changes by 6 mA is:

The correct option is C 24 mAα=0.8 β=α1−α=0.80.2=4 ΔIcΔIB=4⇒ΔIc=4×6=24mA

For a transistor, the value of $α$ is 0.8. The transistor is connected in common-emitter configuration. The change in the collector current when the base current changes by 6 mA is:

The correct option is C 24 mA
$α = 0.8$
$β = \frac{α}{1 - α} = \frac{0.8}{0.2} = 4$
$\frac{Δ I_{c}}{Δ I_{B}} = 4 \Rightarrow Δ I_{c} = 4 \times 6 = 24 m A$